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If Sn=1^2+(1^2+2^2)+(1^2+2^2+3^2)+ upto ...

If `S_n=1^2+(1^2+2^2)+(1^2+2^2+3^2)+` upto `n` terms, then `S_n=(n(n+1)^2(n+2))/(12)` b. `S_n=(n(n-1)^2(n+2))/(12)` c. `S_(22)=3276` d. `S_(22)=23275`

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