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If Sn=sum(r=1)^n r/(1. 3. 5. 7 (2r+1)) t...

If `S_n=sum_(r=1)^n r/(1. 3. 5. 7 (2r+1))` then `S_n=1/2[1-1/(1. 3. 5 (2n+1))]` b. `S_oo=1/2` c. `1/4[1+1/(1. 3. 5 dot(2n-1))]` d. `S_oo=1/4`

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