If `f(x)={min{x ,x^2}; xgeq0,min"("2x ,x^2-1"}"; x<0` , then number of points in the interval `[-2,2]` where `f(x)` is non-differentiable is: 1 (b) 2 (c) 3 (d) 4

The number of points at which the function, f (x)={{:(min {|x|"," x ^(2)}),(min (2x -1"," x^(2)}):}if x in (-oo,1) otherwise is not differentiable is:

If f(x)=min(1,x^2,x^3), then

f(x)=min({x,x^(2)} and g(x)=max{x,x^(2)}

If f(x) min(x,x^(2),x^(3)) , then

f(x)={x+1, x<0,x^2, xgeq0 and g(x)={x^3, x<1, 2x-1, xgeq1 Then find f(g(x)) and find its domain and range.

Let f (x) = {{:(min (x"," x ^(2)), x ge 0),( max (2x "," x-1), x lt 0):}, then which of the following is not true ?

Which of the following function is not differentiable at x=0? f(x)={(0 ,, xgeq0),(x^2 ,, x<0):} , f(x)=x^2sgn(x)

Let f(x)=f_1(x)-2f_2 (x) , where ,where f_1(x)={((min{x^2,|x|},|x|le 1),(max{x^2,|x|},|x| le 1)) and f_2(x)={((min{x^2,|x|},|x| lt 1),({x^2,|x|},|x| le 1)) and let g(x)={ ((min{f(t):-3letlex,-3 le x le 0}),(max{f(t):0 le t le x,0 le x le 3})) for -3 le x le -1 the range of g(x) is

Let f(x) = {-x^2 ,for x<0x^2+8 ,for xgeq0 Find x intercept of tangent to f(x) at x =0 .

If f(x)=x^2+2b x+2c^2 and g(x)= -x^2-2c x+b^2 are such that min f(x)> m a x g(x) , then the relation between b and c is