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If `m_1` and `m_2` are the roots of the equation `x^2-a x-a-1=0` , then the area of the triangle formed by the three straight lines `y=m_1x ,y=m_2x ,` and `y=a(a!=-1)` is `(a^2(a+2))/(2(a+1))ifa >-1` `(-a^2(a+2))/(2(a+1))ifa >-1` `(-a^2(a+2))/(2(a+1))if-2

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