There is a group of 6 persons. They play a game in which each has to select a number from 1 to 4. Let `A_n` is event that n persons have selection of same number, then `P(A_5)=(18)/(4^6)` (b) `P(A_5)=(18)/(4^5)` `P(A_6)=1//4^5` (d) `P((A_5)/(A_6))=1/2`

Let E and F be two independent events. The probability that exactly one of them occurs is 11/25 and the probability if none of them occurring is 2/25 . If P(T) denotes the probability of occurrence of the event T , then (a) P(E)=4/5,P(F)=3/5 (b) P(E)=1/5,P(F)=2/5 (c) P(E)=2/5,P(F)=1/5 (d) P(E)=3/5,P(F)=4/5

If A and B are two events such that P(AcupB)=(5)/(6), P(A)=(1)/(3) and P(B)=(3)/(4) , then A and B are

If ^nC_4, ^nC_5, ^nC_6 are in A.P. then the value of n is

If 1/3+1/2+1/x=4, then x=? (a) 5/(18) (b) 6/(19) (c) (18)/5 (d) (24)/(11)

Four numbers are such that the first three are in.A.P while the last three are in G.P. If the first number is 6 and common ratio of G.P. is 1/2 the the number are (A) 6,8,4,2 (B) 6,10,14,7 (C) 6,9,12,6 (D) 6,4,2,1

Select those rational numbers which can be written as a rational numbers with numerator 6: 1/(22),2/3,3/4,4/(-5),5/6,\ (-6)/(7\ ),\ (-7)/8

4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is :

In how many different ways can the first 12 natural numbers be divided into three different groups such that numbers in each group are in A.P.? a. 1 b. 5 c. 6 d. 4

Consider a number N = 2 1 P 5 3 Q 4. The number of ordered pairs (P,Q) so that the number 'N' is divisible by 44, is

Let Aa n dB are events of an experiment and P(A)=1//4, P(AuuB)=1//2, then value of P(B//A^c) is 2//3 b. 1//3 c. 5//6 d. 1//2