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If sum(k=0)^5^5Cksink xcos(5-k)x=Nsin5x ...

If `sum_(k=0)^5^5C_ksink xcos(5-k)x=Nsin5x` where `N` is some natural number then the value of `N` is divisible by `2` b. `4` c. `8` d. `16`

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