Number of digits in integral part of `60^(12)+60^(-12)-60^(-15)is ("given log"2=0.3030.log3=0.4771)`

Find the number of digits in (72)^15 without actual computation. Given log2=0.301, log3=0.477.

Let S denotes the antilog of 0.5 to the base 256 and K denotes the number of digits in 6^(10) (given log_(10)2=0.301 , log_(10)3=0.477 ) and G denotes the number of positive integers, which have the characteristic 2, when the base of logarithm is 3. The value of SKG is

Number of zeros after decimal before first significant dign in the number (0.bar3)^10000 is (Given log_10 3 = 0.4771 )

Comprehension 3 If P is the non negative characteristic of (log)_(10)N , the number of significant digit in N\ i s\ P+1 . If P is the negative characteristic of (log)_(10)N , then number of zeros after decimal before a significant digit start are P-1.( Use log_(10)\ 2=0. 301.(log)_(10)3=0. 4771 ) Number of significant digit in N , where N=(5/3)^(100), is- a. 23 b. \ 22 c. \ 21 d. none

How many zeroes are there between the decimal point and first significasnt digits in (0.0504)^10 . Given log2=0.301,log3=0.477 nd log7= 0.845

Comprehension 3 If P is the non negative characteristic of (log)_(10)N , the number of significant digit in N\ i s\ P+1 . If P is the negative characteristic of (log)_(10)N , then number of zeros after decimal before a significant digit start are P-1.( Use log_(10)\ 2=0. 301.(log)_(10)3=0. 4771 ) Number of zeros after decimal before a significant digit start in N , where N=((81)/(16))^(-25)i s- a. 16 b. \ 17 c.18 d. 19

Find the numbers of zeroes between the decimal point and first significant digit of (0.036)^16 , where log 2=0.301 and log 3=0.477 .

A first order reaction takes 20 minutes for 25% decomposition. Calculate the time when 75% of the reaction will be completed. (Given, log2=0.3010,log3=0.4771,log4=0.6021 )

Count total number of S.F in 1.60 xx 10^(-12) .

Suppose U denotes the number of digits in the number (60)^(100) and M denotes the number of cyphers after decimal, before a significant figure comes in (8)^(-296) . If the fraction U/M is expressed as rational number in the lowest term as p//q (given log_(10)2=0.301 and log_(10)3=0.477 ) . The value of q is