The area bounded by `x^2+y^2-2x=0a n dy=sinpi/2x` in the upper half of the circle is `pi/2-4/pi` 2. `pi/4-2/pi` 3. `pi-8/pi` 4. `pi+8/pi` 5. `pi/2+4/pi`

The area bounded by f(x)=sin^(-1)(sinx) and g(x)=pi/2-sqrt(pi^(2)/2-(x-pi/2)^(2)) is

The area bounded by the curves x^2+y^2=1,x^2+y^2=4 and the pair of lines sqrt3 x^2+sqrt3 y^2=4xy , in the first quadrant is (1) pi/2 (2) pi/6 (3) pi/4 (4) pi/3

Principle Argument of z=(2+i)/((1+i)^(200)(1-2i)) is 1 dot-pi/4 2. pi/8 3. -pi/2 4. pi/4 5. pi/2

int_(-2)^2|"xcospix"|"dx" has the value equal to 8/pi b. 4/pi c. 2/pi d. pi/2

The angles at which the circles (x-1)^2+y^2=10a n dx^2+(y-2)^2=5 intersect is pi/6 (b) pi/4 (c) pi/3 (d) pi/2

If cos^2 2x+2cos^2x=1,\ x in (-pi,pi), then x can take the values : +-pi/2 (b) +-pi/4 +-(3pi)/4 (d) none of these

Let f(x) be a non-negative continuous function such that the area bounded by the curve y=f(x), the x-axis, and the ordinates x=pi/4a n dx=beta>pi/4i sbetasinbeta+pi/4cosbeta+sqrt(2)betadot Then f(pi/2) is (pi/2-sqrt(2)-1) (b) (pi/4+sqrt(2)-1) -pi/2 (c) (1-pi/4+sqrt(2))

The angle of intersection of the curves y=2\ sin^2x and y=cos2\ x at x=pi/6 is (a) pi//4 (b) pi//2 (c) pi//3 (d) pi//6

The ratio of the perimeter (circumference) and diameter of a circle is (a) pi\ (b) 2pi (c) pi/2 (d) pi/4

Area lying in the first quadrant and bounded by the circle x^2+y^2=4 and the lines x= 0 a n dx= 2 is(A) pi (B) pi/2 (C) pi/3 (D) pi/4