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The point (-4,5) is vertex of a square a...

The point `(-4,5)` is vertex of a square and one of its diagonal is `7x-y+8=0.` The equation of other diagonal is `7x-y+23=0` `7y+x+=30` `7y+x=31` `x-7y=30` `x+7y+31=0`

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Two consecutive sides of a parallelogram are 4x+5y=0 and 7x+2y=0. If the equation of one diagonal is 11 x+7y=9, Equation of other diagonal : (A) 11x + 7y =0 (B) 3x - 5y + 5 = 0 (C) 7x + 11y = 0 (D) x-y =0

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One diagonal of a square is along the line 8x-15 y=0 and one of its vertex is (1, 2). Then the equations of the sides of the square passing through this vertex are (a)23 x+7y=9,7x+23 y=53 (b)23 x-7y+9=0,7x+23 y+53=0 (c)23 x-7y-9=0,7x+23 y-53=0 (d)none of these

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Use matrix method to solve the equations 5x - 7y = 2 and 7x - 5y = 3

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