Equation of the locus of all points such that the difference of its distances from `(-3,-7), (-3,3)` is `8` is (A) `(x+3)^2/16-(y+2)^2/9=1` (B) `(x+3)^2/9-(y+2)^2/16=-1` (C) `(x+3)^2/9-(y+2)^2/19=1` (D) `(x+3)^2/7-(y+2)^2/19=-1`

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^(2)+y^(2))^(2)=4xy (b) (x^2-y^2)=1/9 (c) (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

Let R(x_1, y_1)a n dS(x_2,y_2) be the end points of latus rectum of parabola y^2=4xdot The equation of ellipse with latus rectum R S and eccentricity 1/2 are (a > b) ((3x+1)^2)/(64)+(3y^2)/8=1 ((3x-7)^2)/(64)+(3y^2)/8=1 ((3x+1)^2)/8+(3y^2)/(64)=1 ((3x-7)^2)/8+(3y^2)/(64)=1

Find the values o x and y if: (3x-1,2y-7)=(9,-9)

The equation of the circle passing through the foci of the ellipse (x^2)/(16)+(y^2)/9=1 , and having centre at (0, 3) is (1) x^2+y^2-6y+7=0 (2) x^2+y^2-6y-5=0 (3) x^2+y^2-6y+5=0 (4) x^2+y^2-6y-7=0

Equation of the hyperbola whose vertices are (+-3,0) and foci at (+-5,0) is a. 16 x^2-9y^2=144 b. 9x^2-16 y^2=144 c. 25 x^2-9y^2=225 d. 9x^2-25 y^2=81

The centre of the ellipse (x+y-3)^(2)/9+(x-y+1)^(2)/16=1 is

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

Multiply: (i) ( a/7+(a^2)/9)b y\ (b/2-(b^2)/3) (ii) (3x^2y-5x y^2)b y\ (1/5x^2+1/3y^2)

Find the equations of the tangents drawn from the point (2, 3) to the ellipse 9x^2+16 y^2=144.