Odds 8 to 5 against a person who is 40 years old living till he is 70 and 4 to 3 against another person now 50 till he will be living 80. Probability that exactly one of them will be alive next 30 years `(59)/(91)` 2. `(44)/(91)` 3. `(51)/(91)` 4. `(32)/(91)` 5. `(47)/(91)`

Supposing that it is 8 to 7 against a person who is now 30 years of age living till he is 60 and 2 to 1 against a person who is now 40 living till he is 70 , find the probability that at least one of these persons will be alive 30 years hence .

The odds against a husband who is 45 years old, living till he is 70 are 7:5 and the odds against his wife who is now 36, living till she is 61 are 5:3. Find the probability that the couple will be alive 25 years hence, exactly one of them will be alive 25 years hence, none of them will be alive 25 years hence, at least one of them will be alive 25 years hence.

The odds in favour of A whose age is 45 years will alive upto 60 years are 7:10 . The odds against of B whose age is 50 years, will alive upto 65 years are 3:2 . Find the probability that at least one will alive upto next 15 years.

Four person independently solve a certain problem correctly with probabilities 1/2,3/4,1/4,1/8dot Then the probability that he problem is solve correctly by at least one of them is (235)/(256) b. (21)/(256) c. 3/(256) d. (253)/(256)

The probability that a person will get an electric contact is 2/5 and the probability that he will not get plumbing contract is 4/7 . If the probability of getting at least one contract is 2/3 , what is the probability that he will get both.

The probability that a person will get an electric contract is 2/5 and the probability that they will not get plumbing contracts 4/7dot if the probability of getting at least one contract is 2/3 , what is the probability that he will get both?

The probability that a person will win a game is (2)/(3) and the probability that he will not win a horse race is (5)/(9) . If the probability of getting in at least one of the events is (4)/(5) ,what is the probability that he will be successful in both the events ?

Simplify and write each of the following in exponential from: (i) (9^8xx(x^2)^5)/((27)^4xx(x^3)^2) (ii) (3^2xx7^8xx13^6)/(21^2xx91^3)

All the jacks, queens, kings, and aces of a regular 52 cards deck are taken out. The 16 cards are throughly shuffled and may opponent, a person who always tells the truth, simultaneously draws two cards at random and says, "I hold at least one ace". The probability that he holds two aces is (a)2/8 (b)4/9 (c)2/3 (d)1/9

Express in terms of log 2 and log 3 : (i) log 36 (ii) log 144 (iii) log 4.5 (iv) "log"(26)/(51) - "log" (91)/(119) (v) "log"(75)/(16) - "2 log" (5)/(9) + "log" (32)/(243)