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Let `f(x)` be a function such that `2f(x)+f((x+1)/(x-1))=x.` `AAx in R-{1}dot` If `3f(x)+f((x+1)/(x-1))=lambdax.` `AAx in R-{1},` then value of `lambda` is

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RESONANCE DPP ENGLISH-JEE MAINS-All Questions
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