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A five digits number divisible by 3 is t...

A five digits number divisible by 3 is to be formed using the number 0,1,2,3,4 and 5 without repetition. The number of such numbers are `m^(3)` then m is equal to

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A five digit number divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 and 5, without repetition. The total number of ways this can be done, is

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A three-digit number is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition.

A 5-digit number divisible by 3 is to be formed using the number 0,1,2,3,4 and 5 without repetiition. Find total of ways in whiich this can be done.

A five digit number divisible by 3 is to be formed using the digits 0,1,2,3,4 and 5 without repetitioon. If the tota number of ways in which this casn bedone is n^3, then |__n= (A) 720 (B) 120 (C) 48 (D) 12

Statement-1: A 5-digit number divisible by 3 is to be formed using the digits 0,1,2,3,4,5 without repetition, then the total number of ways this can be done is 216. Statement-2: A number is divisible by 3, if sum of its digits is divisible by 3.

The sum of the digits in unit place of all the numbers formed using the digits 3,4,5,6 without repetitions, the no. of such numbers are

Total 5-digit numbers divisible by 3 can be formed using 0, 1, 2, 3, 4, 5 if repetition of digits is not allowed is:

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