`1+i^(10)+i^(110)+i^(1000)`

Show that 1+i^(10)+i^(20)+i^(30) is a real number.

Simplify the following : (i) 1+ i^(5)+i^(10)+i^(15) (ii) (1+i)^(4)+(1+(1)/(i))^(4) (iii) i^(n)+i^(n+1)+i^(n+2)+i^(n+3)

If n= 10, sum_(i=1)^(10) x_(i) = 60 and sum_(i=1)^(10) x_(i)^(2) = 1000 then find s.d.

If I_m=int_1^e (lnx)^m dx ,m in N , then I_(10)+10 I_9 is equal to (A) e^(10) (B) (e^(10))/(10) (C) e (D) e-1

the value of ((i^(11)+i^(12)+i^(13)+i^(14) +i^(15)))/((1+i)) is

Convert the following fractions into decimals. (i) 2/10 (ii) 11/10 (iii) (11)/(100) (iv)(234)/(1000)

Express the following fractions as decimals: (i) (79)/(10) (ii) (785)/(100) (iii) (1359)/(1000) .

Given Sigma_(i=1)^(20) a_i=100, Sigma_(i-1)^(20) a_i^2=600, Sigma_(i-1)^(20) b_i=140, Sigma_(i-1)^(20)b_i^2=1000 , where a_i,b_i denotes length and weight of an observations. Then which is more varying ?

Write each of the following as decimals: (i) 20+9+4/(10)+1/(100) (ii) 30\ +4/(10)+8/(100)+3/(1000)\

Write each of the following as decimals: (i) 137+5/(100) (ii) 7/(10)+6/(100)+4/(1000)