The from `a+ib` is given : `(7-i2)-(4+i)+(-3+i5)` simplify it.

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Express each of the following in the standerd from a + ib (i) (5+4i)/(4+ 5i) (ii) ((1 +i)^(2))/(3-i) (iii) (1)/(1-cos theta + 2i sintheta)

Express the following in the form of a + ib . (i) ( 1/2 + 3i)^(2) (ii) ( 2+ 3i) ( 2-3i)

Evaluate (5-7i) +(2+4i).

Simplify: (3-7i)^(2)

(4+3i) +(7-4i)-(3+5i)+i^(25) is equal to

Simplify the following: (-i)(2i)(- 1/8i)^3

Evaluate (2-7i)/(3+5i)

Simplify: (9+4i) ((3)/(2)-i) (9-4i)

Simplify the following: (-5i)(1/8i)