Show that `costheta` `[[costheta, sintheta],[-sintheta, cos theta]]`+`sin theta` `[[sintheta ,-cos theta],[costheta, sin theta]]`=1

Show that costheta.[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta.[{:(sintheta,-costheta),(costheta,sintheta):}]=I.

Simplify: cos theta[{:(costheta,sintheta),(-sintheta,costheta):}]+sintheta[{:(sin theta ,-costheta),(costheta, sintheta):}]

costheta[{:(costheta,-sin theta),(sintheta,costheta):}]+sintheta[{:(sintheta,costheta),(-costheta,sintheta):}]=?

Simplify the following : cos theta [{:(costheta,-sintheta ),(sintheta,costheta ):}]+sintheta[{:(sintheta,costheta),(-costheta,sintheta):}]

If cos theta-4sintheta=1, the sintheta+4costheta=

The value of f(pi/6) where f(theta)=|{:(cos^2theta,costhetasintheta,-sintheta),(costhetasintheta,sin^2theta,costheta),(sintheta,-costheta,0):}|

Evaluate the following: |costheta, -sin theta],[sin theta, cos theta]|

If {:A=[(cos theta,sintheta),(-sintheta,costheta)]:}," then A.A' is

Prove that : (sintheta +sin2theta)/(1+costheta+cos2theta)=tantheta

If sintheta,tantheta,costheta are in G.P. then 4sin^2theta-3sin^4theta+sin^6theta=?