If `A=[[cos 2 theta, sin 2 theta],[-sin2theta, cos2theta]]`, find `A^2`

sin^(3)theta + sin theta - sin theta cos^(2)theta =

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] ,then f ( pi / 7) is

if A=[{:(costheta,sin theta ),(-sin theta,costheta):}] , then show that : A^(2)=[{:(cos2theta,sin2theta),(-sin2theta,cos2theta):}]

If x=a(cos 2 theta+2 theta sin 2 theta) " and" y=a(sin 2 theta - 2 theta cos 2 theta) , find (d^(2)y)/(dx^(2)) " at" theta =(pi)/(8) .

(1+sin2theta+cos2theta)/(1+sin2theta-cos2theta)=?

(1+sin 2theta+cos 2theta)/(1+sin2 theta-cos 2 theta) =

If |(1+sin^2 theta,sin^2 theta,sin^2 theta),(cos^2 theta,1+cos^2 theta,cos^2 theta),(4sin 4 theta,4sin4theta,1+4sin4theta)|=0, then ... sin 4theta equal to ....

Prove that sin(2theta)/(1-cos2theta)=cot theta

Prove that cos^6 theta+ sin^6 theta= 1-3sin^2 theta cos^2 theta

Prove that: (sin2theta)/(1-cos2theta)=cottheta