In the binomial expansion of `(a-b)^(n) , n ge 5`, the sum of 5th and 6th terms is zero, then `(a)/(b)` equals

In the binomial expansion of (a-b)^n , ngeq5, the sum of 5th and 6th terms is zero, then a/b equals (1) 5/(n-4) (2) 6/(n-5) (3) (n-5)/6 (4) (n-4)/5

In the binomial expansion of (a - b)^n , n ge 5 the sum of the 5th and 6th term is zero , then find a/b

In the binomial expansion of (a-b)^n,ngeq5, the sum of the 5th and 6th term is zero. Then a//b equals (n-5)//6 b. (n-4)//5 c. n//(n-4) d. 6//(n-5)

If in the expansion of (a-2b)^(n) , the sum of 5^(th) and 6^(th) terms is 0, then the values of a/b is (a) (n-4)/(5) (b) (2(n-4))/(5) (c) (5)/(n-4) (d) (5)/(2(n-4))

If in the expansion of (a-2b)^n , the sum of 5th and 6th terms is 0, then the values of a/b a. (n-4)/5 b. (2(n-4))/5 c. 5/(n-4) d. 5/(2(n-4))

In the binomial expansion of (1+x)^(43) , the coefficients of the (2r+1) th and (r+2) th terms are equal. Then r=

In the binomial expansion of (a+b)^n , coefficients of the fourth and thirteenth terms are equal to each other. Find n .

In the binomial expansion of (1 + x)^(10) , the coefficeents of (2m + 1)^(th) and (4m + 5)^(th) terms are equal. Value of m is

Find a if the 7th and 18th terms of the expansion (2+a)^(50) are equal.

If in any binomial expansion a, b, c and d be the 6th, 7th, 8th and 9th terms respectively, prove that (b^2-ac)/(c^2-bd)=(4a)/(3c)