I three consecutive coefficients in the expansion of `(1+x)^n` are in the ratio 6:33:110, find n and r.

If three consecutive coefficients in the expansion of (1+x)^n be 56, 70 and 56, find n and the position of the coefficients.

The greatest coefficient in the expansion of (1+x)^(2n) is

The coefficients of three consecutive terms in the expansion of (1+a)^n are in the ratio 1: 7 : 42. Find n.

If there are three successive coefficients in the expansion of (1+2x)^(n) which are in the ratio 1:4:10 , then 'n' is equal to :

If the coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42, then find the value of ndot

If the coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42, then find the value of ndot

If the coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42, then find the value of ndot

The sum of the coefficient in the expansion of (1 + x+x^2)^n is

If the three consecutive coefficients in the expansion of (1+x)^n are 28, 56, and 70, then the value of n is.

The coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 182:84:30 . prove that n=18