The coefficients of three consecutive terms in the expansion of `(1+x)^n` are in the ratio `182:84:30`. prove that `n=18`

The coefficients of three consecutive terms in the expansion of (1+a)^n are in the ratio 1: 7 : 42. Find n.

If the coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42, then find the value of ndot

If the coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42, then find the value of ndot

If the coefficients of three consecutive terms in the expansion of (1+x)^n are in the ratio 1:7:42, then find the value of ndot

If the coefficients of three consecutive terms in the expansion of (1+x)^n be 76, 95 and 76 find n .

Write the coefficient of the middle term in the expansion of (1+x)^(2n) .

If the coefficients of three consecutive terms in the expansion of (1+x)^n are 45, 120 and 210 then the value of n is

If the coefficients of three consecutive terms in the expansion of (1 + x)^(n) are 165,330 and 462 respectively , the value of n is is

I three consecutive coefficients in the expansion of (1+x)^n are in the ratio 6:33:110, find n and r.

The coefficients of three consecutive terms of (1+x)^(n+5) are in the ratio 5:10:14. Then n= ___________.