If n A.M.'s are inserted between 1 and 31 such
that the ratio of the `7^(th) and (n-1)^(th)` mean is ` 5 : 9`
then the value of n is

n A.M.\'s are inserted between 1 and 31 such that the ratio of the 7th and (n-1) th means is 5:9. Find n.

If n arithmetic means are inserted between 1 and 31 such that the ratio of the first mean and nth mean is 3:29 then the value of n is a. 10 b. 12 c. 13 d. 14

If n arithemetic means are inserted between 20 and 80 such that the ratio of first mean to the last mean is 1:3, then find the value of n .

There are m arithmetic means between 5 and -16 such that the ratio of the 7th mean to the (m-7)th mean is 1:4. Find the value of m.

Between 1 and 31 are inserted m arithmetic mean so that the ratio of the 7th and (m-1)t h means is 5:9. Find the value of mdot

Between 1 and 31 are inserted m arithmetic mean so that the ratio of the 7th and (m-1)t h means is 5:9. Find the value of mdot

Let n AM's are inserted between - 7 and 65 If the ratio of 2^(nd) and 7^(th) means is 1:7 , then n is equal to

There are 'n' A.M.'s between 2 and 41. The ratio of 4th and (n - 1)th mean is 2 : 5, find the value of n.

If n arithmetic means are inserted between 7 and 71 such that 5^(th) A.M. is 27 then n= ?

n' arithmetic means are there between 4 and 36. If the ratio of 3rd and (n-2)th mean is 2:3, find the value of n.