the sum of terms equidistant from the beginning and end in an AP is equal to …………. .

Statement -1: If a_(1),a_(2),a_(3), . . . . .,a_(n), . . . is an A.P. such that a_(1)+a_(4)+a_(7)+ . . . .+a_(16)=147 , then a_(1)+a_(6)+a_(11)+a_(16)=98 Statement -2: In an A.P., the sum of the terms equidistant from the beginning and the end is always same and is equal to the sum of first and last term.

Show that in an A.P. the sum of the terms equidistant from the beginning and end is always same and equal to the sum of first and last terms.

In a finite G.P. the product of the terms equidistant from the beginning and the end is always same and equal to the product of first and last term.

If n A.Ms are inserted between two numbers, prove that the sum of the means equidistant from the beginning and the end is constant.

Prove that the sum of nth term from the beginning and nth term from the end of an A.P. is· constant.

The first and the last terms of an A.P. are a\ a n d\ l respectively. Show that the sum of nth term from the beginning and nth term from the end is a+ldot

If an A.P. consists of n terms with first term a and n^(th) term l then show that the sum of the m^(th) term from the beginning and the m^(th) term from the end is (a+l) .

The sum of the binomial coefficients of the 3rd, 4th terms from the beginning and from the end of (a+ x)^n is 440 then n =

Sum of coefficients of expansion of B is 6561 . The difference of the coefficient of third to the second term in the expansion of A is equal to 117 . The ratio of the coefficient of second term from the beginning and the end in the expansion of B , is

If in an A.P. the sum of m terms is equal of n and the sum of n terms is equal to m , then prove that the sum of -(m+n) terms is (m+n) .