LetS be the sum, P the product, and R the sum of reciprocals of n terms in a G.P. Prove that `P^(2)R^(n)=S^(n)`.

Let S be the sum, P the product, and R the sum of reciprocals of n terms in a G.P. Prove that P^2R^n=S^ndot

Let S e the sum, P the product, adn R the sum of reciprocals of n terms in a G.P. Prove that P^2R^n=S^ndot

if S is the sum , P the product and R the sum of reciprocals of n terms in G.P. prove that P^2 R^n=S^n

if S is the sum , P the product and R the sum of reciprocals of n terms in G.P. prove that P^2 R^n=S^n

If S is the sum, P the product and R the sum of the reciprocals of n terms in G.P., prove that P^(2)= ((S)/(R))^(n) .

Let S be the sum, P be the product and R be the sum of the reciprocals of 3 terms of a G.P. then P^2R^3: S^3 is equal to (a) 1:1 (b) (common ratio)^n :1 (c) (First term)^2(common ratio)^2 (d) None of these

If S be the sum, p the product and R the sum of the reciprocals of n terms of a G.P., then (S/R)^n is equal to

If S be the sum P the product and R be the sum of the reciprocals of n terms of a GP then p^2 is equal to S//R b. R//S c. (R//S)^n d. (S//R)^n

Write the n t h term of an A.P. the sum of whose n terms is S_n .

If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms , prove that P^(2)=(ab)^(n) .