If z1, z2,z3 are the roots of cubic 3z^3...

If `z_1, z_2,z_3` are the roots of cubic `3z^3+3a z^2=a^2z+b=0` then find the value of `1/(z_1-z_2)+1/(z_2-z_3)+1/(z_3-z_1)` `3a+b` b. `a+b` c. `6` d. `0` e. `b`

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