Let `z_1=6+i and z_2=4-3i`. If z is a complex number such thar arg `((z-z_1)/(z_2-z))= pi/2` then (A) `|z-(5-i)=sqrt(5)` (B) `|z-(5+i)=sqrt(5)` (C) `|z-(5-i)|=5` (D) `|z-(5+i)|=5`

Let z_1=10+6i and z_2=4+6idot If z is any complex number such that the argument of ((z-z_1))/((z-z_2)) is pi/4, then prove that |z-7-9i|=3sqrt(2) .

If z be any complex number (z!=0) then arg((z-i)/(z+i))=pi/2 represents the curve

Let z be a complex number such that |(z-5i)/(z+5i)|=1 , then show that z is purely real

If |z-4/2z|=2 then the least of |z| is (A) sqrt(5)-1 (B) sqrt(5)-2 (C) sqrt(5) (D) 2

If z is a complex number such that |z|=4 and a r g(z)=(5pi)/6 , then z is equal to -2sqrt(3)+2i b. 2sqrt(3)+i c. 2sqrt(3)-2i d. -sqrt(3)+i

If z is a complex number such that |z|=4 and a r g(z)=(5pi)/6 , then z is equal to -2sqrt(3)+2i b. 2sqrt(3)+i c. 2sqrt(3)-2i d. -sqrt(3)+i

If z_1=10+6i and z_2=4+2i be two complex numbers and z be a complex number such that a r g((z-z_1)/(z-z_2))=pi/4 , then locus of z is an arc of a circle whose (a) centre is 5+7i (b) centre is 7+5i (c) radius is sqrt(26) (d) radius is sqrt(13)

Let z be a complex number such that |z|+z=3+I (Where i=sqrt(-1)) Then ,|z| is equal to

If z is any complex number satisfying |z-3-2i|lt=2 then the maximum value of |2z-6+5i| is

Find the complex number z satisfying the equation |(z-12)/(z-8i)|= (5)/(3), |(z-4)/(z-8)|=1