`z=x+iy` satisfies `arg(z+2)=arg(z+i)` then
(A) `x+2y+1=0`
(B) `x+2y+2=0`
(C) `x-2y+1=0`
(D) `x-2y-2=0`

If arg(z-1)=arg(z+3i) , then find (x-1):y , where z=x+iy .

If arg(z-1)=arg(z+2i) , then find (x-1):y , where z=x+iy

The equation of the plane passing through the intersection of the planes x+2y+3z+4=0a dn 4x+3y+2z+1=0 and the origin ils (A) 3x+2y+z+1=0 (B) 3x+2y+z=0 (C) 2x+3y+z=0 (D) x+y+z=0

A plane through the line (x-1)/1=(y+1)/(-2)=z/1 has the equation (A) x+y+z=0 (B) 3x+2y-z=1 (C) 4x+y-2z=3 (D) 3x+2y+z=0

The equation of the plane containing the line 2x+z-4=0 nd 2y+z=0 and passing through the point (2,1,-1) is (A) x+y-z=4 (B) x-y-z=2 (C) x+y+z+2=0 (D) x+y+z=2

for every point (x,y,z) on the y-axis: (A) x=0,y=0 (B) x=0,z=0 (C) y=0,z=0 (D) y!=0,x=0,z=0

The equation of the plane thorugh the point (-1,2,0) and parallel to the lines x/3=(y+1)/0=(z-2)/(-1) and (x-1)/1=(2y+1)/2=(z+1)/(-1) is (A) 2x+3y+6z-4=0 (B) x-2y+3z+5=0 (C) x+y-3z+1=0 (D) x+y+3z-1=0

A plane which passes through the point (3,2,0) nd the line (x-4)/1=(y-7)/5=(z-4)/4 is (A) x-y+z=1 (B) x+y+z=5 (C) x+2y-z=1 (D) 2x-y+z=5

The locus of point such that the sum of the squares of its distances from the planes x+y+z=0, x-z=0 and x-2y+z=0 is 9 is (A) x^2+y^2+z^2=3 (B) x^2+y^2+z^2=6 (C) x^2+y^2+z^2=9 (D) x^2+y^2+z^2=12

The image of plane 2x-y+z=2 in the plane mirror x+2y-z=3 is (a) x+7y-4x+5=0 (b) 3x+4y-5z+9=0 (c) 7x-y+2z-9=0 (d) None of these