If `sec^-1 ((z-2)/i)` lies between 0 and `pi/2` , where `z=x+iy` then (A) `xgt2,ygt1` (B) `x=2,ygt1` (C) `x=2,y=1` (D) `xlt2,y=1`

If arg(z-1)=arg(z+2i) , then find (x-1):y , where z=x+iy

z=x+iy satisfies arg(z+2)=arg(z+i) then (A) x+2y+1=0 (B) x+2y+2=0 (C) x-2y+1=0 (D) x-2y-2=0

If Real ((2z-1)/(z+1)) =1, then locus of z is , where z=x+iy and i=sqrt(-1)

If Real ((2z-1)/(z+1)) =1, then locus of z is , where z=x+iy and i=sqrt(-1)

The number of solutions of sqrt(2)|z-1|=z-i, where z=x+iy is (A) 0 (B) 1 (C) 2 (D) 3

If |(z +4)/(2z -1)|=1, where z =x +iy. Then the point (x,y) lies on a:

If |(z +4)/(2z -1)|=1, where z =x +iy. Then the point (x,y) lies on a:

The equation of the plane containing the line 2x+z-4=0 nd 2y+z=0 and passing through the point (2,1,-1) is (A) x+y-z=4 (B) x-y-z=2 (C) x+y+z+2=0 (D) x+y+z=2

A plane which bisects the angle between the two given planes 2x - y +2z - 4 = 0 and x +2y +2z - 2 = 0 , passes through the point: (A) (1,-4,1) (B) (1,4,-1) (C) (2,4,1) (D) (2,-4,1)

A plane through the line (x-1)/1=(y+1)/(-2)=z/1 has the equation (A) x+y+z=0 (B) 3x+2y-z=1 (C) 4x+y-2z=3 (D) 3x+2y+z=0