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If the equation (p+iq)x^2 +(m+ni)x+r=0 h...

If the equation `(p+iq)x^2 +(m+ni)x+r=0` has real root where p,q,m, n and r are real `(!=0) `then `pn^2+rq^2-mnq=` (A) 1 (B) 0 (C) -1 (D) none of these

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