If `|z-25i|le15` then least positive value of `argz=` (A) `pi-tan^-1(3/4)` (B) `tan^-1(3/4)` (C) `tan^-1(4/3)` (D) `pi-tan^-1(4/3)`

tan^(- 1)(1/4)+tan^(- 1)(2/9)=1/2tan^(- 1)(4/3)

tan^(- 1)(1/4)+tan^(- 1)(2/9)=1/2tan^(- 1)(4/3)

The angle between the normals of ellipse 4x^2 + y^2 = 5 , at the intersection of 2x+y=3 and the ellipse is (A) tan^(-1) (3/5) (B) tan^(-1) (3/4) (C) tan^(-1) (4/3) (D) tan^(-1) (4/5)

Show that 2tan^-1 (-3)=-pi/2+tan^-1(-4/3)

Show that 2tan^-1 (-3)=-pi/2+tan^-1(-4/3)

Find value of tan^-1 (3/4)+tan^-1 (3/5)-tan^-1 (8/19)

Prove that : tan^(-1)(1/2) + tan^(-1)(1/3) = tan^(-1)(3/5) + tan^(-1)(1/4) = pi/4

4tan^(- 1)(1/5)=tan^(- 1)(1/70)-tan^(- 1)(1/99)+pi/4

Prove that: tan^-1 (1/3)+tan^-1 (2/9)+tan^-1 (4/33)+… tooo= pi/4

Find the principal values of the following (i) tan^(-1) (tan. (2pi)/(3)) (ii) tan^(-1) (tan (-6))