`x+iy=|[6i,-3i,1],[4,3i,-1],[20,3,i]|`, find x and y.

If |[6i,-3i,1],[ 4, 3i,-1],[ 20, 3,i]|=x+i y , then a. x=3,y=1 b. x=1,y=3 c. x=0,y=3 d. x=0,y=0

Solve (1−i)x+(1+i)y=1−3i, find x and y

If det|6i -3i 1 4 3i-1 20 3 i|=x+i y , then a. x=3,y=1 b. x=1,y=3 c. x=0,y=3 d. x=0,y=0

Find x and y i the matrix A= 1/3 [[1,2,2],[2,1,-2],[x,2,y]] satisfythe condition A A\'=A\'A=I_3

if |(z-6)/(z+8)|=1 , then the value of x in R , where z=x+i|{:(-3,2i,2+i),(-2i,2,4-3i),(2-i,4+3i,7):}| , is

|(3,-3i,x),(4,y,i),(0,2i,-i)|=18+11i is true of (A) x=1,y=2 (B) x=1,y=-1 (C) x=-1,y=1 (D) x=0,y=3

If (A -2I)(A-3I)=0 , when A=[{:(4,2),(-1,x):}] and I=[{:(1,0),(0,1):}] , find the value of x

If A=[(1,3),(3,4)] and A^2-xA-I=0 then find x.

If A=[{:(,4,2),(,1,1):}] , find (A-2I) (A-3I) .

If ((1+i)/(1-i))^3-((1-i)/(1+i))^3 =a+ib find a and b