If ` x^2-ax+b=0` and ` x^2-px+q=0` have a root in common then the second equation has equal roots show that `b+q=(ap)/2`

If x^(2) -ax+b=0 and x^(2)-px + q=0 have a root in common and the second equation has equal roots, show that b + q =(ap)/2 .

If the two equations x^2 - cx + d = 0 and x^2- ax + b = 0 have one common root and the second equation has equal roots, then 2 (b + d) =

IF x^2 +bx +a=0, ax^2+x+b=0 have a common root and the first equation has equal roots then 2a^2+b=

If the equadratic equation 4x ^(2) -2x -m =0 and 4p (q-r) x ^(2) -2p (r-p) x+r (p-q)-=0 have a common root such that second equation has equal roots then the vlaue of m will be :

If the equadratic equation 4x ^(2) -2x -m =0 and 4p (q-r) x ^(2) -2p (r-p) x+r (p-q)-=0 have a common root such that second equation has equal roots then the vlaue of m will be :

If x^2 - cx +d =0 , x^2-ax +b=0 have one common root and second has equal roots then 2 (b+d) =

If x^(2)+ax+b=0 and x^(2)+bx+a=0,(a ne b) have a common root, then a+b is equal to

If the equation x^(2) - 3x + b = 0 and x^(3) - 4x^(2) + qx = 0 , where b ne 0, q ne 0 have one common root and the second equation has two equal roots, then find the value of (q + b) .

If the equation x^2+ax+bc=0" and " x^2-bx+ca=0 have a common root, then a+b+c =

If the equation x^(2)-px+q=0 and x^(2)-ax+b=0 have a comon root and the other root of the second equation is the reciprocal of the other root of the first, then prove that (q-b)^(2)=bq(p-a)^(2) .