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Thus f(0)=f(1) and hence equation f\'(x)...

Thus `f(0)=f(1)` and hence equation `f\'(x)=0` has at least one root between 0 and 1. Show that equation `(x-1)^5+(2x+1)^9+(x+1)^21=0` has exactly one real root.

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Statement-1: Let a,b,c be non zero real numbers and f(x)=ax^2+bx+c satisfying int_0^1 (1+cos^8x)f(x)dx=int_0^2(1+cos^8x)f(x)dx then the equation f(x)=0 has at least one root in (0,2) .Statement-2: If int_a^b g(x)dx vanishes and g(x) is continuous then the equation g(x)=0 has at least one real root in (a,b) . (A) Both 1 and 2 are true and 2 is the correct explanation of 1 (B) Both 1 and 2 are true and 2 is not correct explanation of 1 (C) 1 is true but 2 is false (D) 1 is false but 2 is true