If the difference between the roots of `x^2+ax+b=0` is same as that of `x^2+bx+a= 0` `a!=b`, then:

If the difference between the roots of x^(2) + ax + b = 0 is equal to the difference between the roots of x^(2)+px+q= 0 then a^(2)-p^(2) =

If the difference between the corresponding roots of x^(2)+ax+b=0and x^(2)+bx+a=0 is same and a ne b, then

If the difference between the corresponding roots of the equations x^(2)+ax+b=0 and x^(2)+bx+a=0(a1=b) is the same, find the value of a+b .

if the difference of the roots of the equation x^(2)+ ax +b=0 is equal to the difference of the roots of the equation x^(2) +bx +a =0 ,then

The roots of the equation x^2+ax+b=0 are

If alpha and beta are the roots of x^(2)+ax+b=0 , then prove that (alpha)/(beta) is a root of the equation bx^(2)+(2b-a^(2))x+b=0

If a and b are the odd integers, then the roots of the equation, 2ax^2 + (2a + b)x + b = 0, a!=0 , will be

If alpha , beta are the roots of ax^2+bx +c=0 then (a alpha + b)^(-2)+( a beta + b)^(-2) =

If one root is common is equations x^(2)-ax+b=0 and x^(2 ) +bx-a=0 , then :

If a and b(!=0) are the roots of the equation x^2+ax+b=0 then the least value of x^2+ax+b is