The quadratic equatin `(2x-a)(2x-c)+lamda(x-2b)(x-2d)=0`, (where `0lt4alt4bltclt4d)` has (A) a root between 2 b and 2d for all `lamda` (B) as root between b nd d for all `-velamda` (C) a root between b and d for all `+velamda` (D) none of these

If the equation |x^2+b x+c|=k has four real roots, then a. b^2-4c > 0 and 0 0 and k > (4c-b^2)/4 d. none of these

lf 0 < a < b < c < d , then the quadratic equation ax^2 + [1-a(b+c)]x+abc-d=0 A) Real and distinct roots out of which one lies between c and d B) Real and distinct roots out of which one lies between a and b C) Real and distinct roots out of which one lies between b and c (D) non -real roots

If a lt b lt c lt d , then for any real non-zero lambda , the quadratic equation (x-a)(x-c)+lambda(x-b)(x-d)=0 ,has real roots for

Let f(x)=ax^2-bx+c^2, b != 0 and f(x) != 0 for all x ∈ R . Then (a) a+c^2 2b (c) a-3b+c^2 < 0 (d) none of these

Equation a/(x-1)+b/(x-2)+c/(x-3)=0(a,b,cgt0) has (A) two imaginary roots (B) one real roots in (1,2) and other in (2,3) (C) no real root in [1,4] (D) two real roots in (1,2)

If a ,b ,c ,d in R , then the equation (x^2+a x-3b)(x^2-c x+b)(x^2-dx+2b)=0 has a. 6 real roots b. at least 2 real roots c. 4 real roots d. none of these

If the quadratic equations, a x^2+2c x+b=0 and a x^2+2b x+c=0(b!=c) have a common root, then a+4b+4c is equal to: a. -2 b. 2 c. 0 d. 1

If c ,d are the roots of the equation (x-a)(x-b)-k=0 , prove that a, b are roots of the equation (x-c)(x-d)+k=0.

If the equation a x^2+2b x-3c=0 has no real roots and ((3c)/4) 0 c=0 (d) None of these

If the equation a x^2+b x+c=x has no real roots, then the equation a(a x^2+b x+c)^2+b(a x^2+b x+c)+c=x will have a. four real roots b. no real root c. at least two least roots d. none of these