If x is acute then sqr 1 + sinx / Sqr 1- sinx

int (1-sinx )/ (1-cos x) dx=?

Differentiate tan^(-1){(sqrt(1+sinx)+sqrt(1-sinx))/(sqrt(1+sinx)-sqrt(1-sinx))} , 0 < x < pi

Differentiate tan^(-1){sqrt((1+sinx)/(1-sinx))},\ -pi/2

If (5pi)/(2)ltxlt3pi , then the value of the expression (sqrt(1-sinx)+sqrt(1+sinx))/(sqrt(1-sinx)-sqrt(1+sinx)) is

If sum of the series 1+x log_(|(1-sinx)/(cos x)|)((1+sin x)/(cos x))^(1//2)+x^(2) log_(|(1-sinx)/(cosx)|)((1+sinx)/(cosx))^(1//4)+...oo (wherever defined) is equal to (k(1-x))/((2-x)) , then k is equal to

Differentiate the following function sqrt((1+sinx)/(1-sinx))

int(sinx)/(sqrt(1+sinx))dx

If 2sinx^(@)-1=0 and x^(@) is an acute angle, find: (i) b sinx^(@)" (ii) "x^(@)" (iii) "cosx^(@) and tanx^(@) .

Differentiate logsqrt((1+sinx)/(1-sinx)) with respect to x .

Differentiate sqrt((1+sinx)/(1-sinx)) with respect to x .