For the equation `3x^2+p x+3=0,p >0,` if one of the root is square of the other, then `p` is equal to `1//3` b. `1` c. `3` d. `2//3`

For the equation, 3x^2+p x+3=0,p >0, if one of the roots is square of the other, then ' p ' is equal to: 1/3 (b) 3 (c) 1 (d) None of these

solve the equations x^3 -3x^2 - 6x +8=0 the roots being in A.P

Solve the equation 6x^3 -11x^2 +6x -1=0 the roots being in H.P

solve the equations 32x^3 - 48 x^2 + 22 x -3=0 , the roots being in A.P.

Solve the equation 3x^3 -26 x^2 + 52 x-24 =0 the roots being in G.P

If one root of x^(2)+px+q=0 may be the square pf the other, then p^(3)+q^(2)+q =

If p + iq be one of the roots of the equation x^(3) +ax +b=0 ,then 2p is one of the roots of the equation

In the quadratic equation x^2+(p+i q)x+3i=0,p&q are real. If the sum of the squares of the roots is 8 then: p=3,q=-1 b. p=3,q=1 c. p=-3,q=-1 d. p=-3,q=1

If one root of the equation x^2+a x+3=0 is 1, then the other root is (a) 3 (b) -3 (c) 2 (d) -2

alpha and beta are the roots of the equation x^2+px+p^3=0,(p!=0) . If the point (alpha,beta) lie on the curve x=y^2 then the roots of the given equation are (A) 4,-2 (B) 4,2 (C) 1,-1 (D) 1,1