The matrix of the transformation reflection in the line `x+y=0` is (A) `[(-1,0),(0,-1)]` (B) `[(1,0),(0,-1)]` (C) `[(0,1),(1,0)]` (D) `[(0,-1),(-1,0)]`

If A=[(1,0),(0,1)] then A^4= (A) [(1,0),(0,1)] (B) [(1,1),(0,10)] (C) [(0,0),(1,1)] (D) [(0,1),(1,0)]

the matrix [(0,1),(1,0)] is the matrix reflection in the line

The trnsformation orthogonal projection on X-axis is given by the matrix (A) [(0,1),(0,0)] (B) [(0,0),(0,1)] (C) [(0,0),(1,0)] (D) [(1,0),(0,0)]

If A=[(1,0),(1/2,1)] then A^50 is (A) [(1,25),(0,1)] (B) [(1,0),(25,1)] (C) [(1,0),(0,50)] (D) [(1,0),(50,1)]

The transformation due of reflection of (x,y) through the origin is described by the matrix (A) [(0,0),(0,0)] (B) [(1,0),(0,1)] (C) [(1,0),(0,-1)] (D) [(0,-1),(-1,0)]

If A=[(1,2),(0,1)], then A^n= (A) [(1,2n),(0,1)] (B) [(2,n),(0,1)] (C) [(1,2n),(0,-1)] (D) [(1,n),(0,1)]

The matrix [(0,1),(1,0)] is the matrix of reflection in the line (A) x-y=0 (B) x+y=0 (C) x-y=1 (D) x+y=1

If A= [(0,1),(1,0)] and B= [(0,-x),(x,0)] , then

The orthocentre of the triangle formed by the lines x y=0 and x+y=1 is (a) (1/2,1/2) (b) (1/3,1/3) (c) (0,0) (d) (1/4,1/4)

Using elementary transformations, find the inverse of the matrix : [(2,0,-1),(5, 1, 0),(0, 1, 3)]