For an invertible square matrix of order 3 with real entries `A^-1=A^2` then det A= (A) 1/3 (B) 3 (C) 0 (D) 1

If A is a matrix of order 3, then det(kA) is

If A is an invertible matrix of order 2, then det (A^(-1)) is equal to(a) det (A) (B) 1/(det(A) (C) 1 (D) 0

If A is a non- singular square matrix of the order 3xx3 such that A^2=3A then (A) -3 (B) 3 (C) 9 (D) 27

If A is an invertible matrix of order 2, then det (A^(-1)) is equal to (A) det (A) (B) 1/(det(A) (C) 1 (D) 0

If A is a non-singular square matrix of order 3 such that A^2 = 3A, then value of |A| is A) (-3) B) 3 C) 9 D) 27

If A is a matrix of order 3 and |A|=8 , then |a d j\ A|= (a) 1 (b) 2 (c) 2^3 (d) 2^6

If A is an invertible matrix of order 3xx3 such that |A|=2 . Then, find |a d j\ A| .

If A is invertible matrix of order 3xx3 , then |A^(-1)| is equal to…………

If A is an invertble matrix of order 2 then (det A ^-1) is equal to- a.det A b.1/ det A c. 1 d. 0

If A is a square matrix of order 3 such that |A|=2 , then |(adjA^(-1))^(-1)| is