If `I=[1 0 0 1]` , `J=[0 1-1 0]` and `B=[costhetasintheta-sinthetacostheta]` , then `B` equals `Icostheta+Jsintheta` (b) `Isintheta+Jcostheta` (c) `Icostheta-Jsintheta` (d) ` Icostheta+Jsintheta`

If I=[(1 ,0),( 0, 1)] , J=[(0, 1),(-1 ,0)] and B=[(costheta,sintheta),(-sintheta,costheta)] , then B equals a) Icostheta+Jsintheta (b) Isintheta+Jcostheta (c) Icostheta-Jsintheta (d) Icostheta+Jsintheta

If I= [{:(,1,0),(,0,1):}], J=[{:(,0,1),(,-1,0):}]and B=[{:(,cos theta,sin theta),(,-sin theta,cos theta)]:}"then B"=

If thetainRandi=sqrt(-1),"then"((1+sintheta+icostheta)/(1+sintheta-icostheta))^(n) is equal to

If A(theta)=[[sintheta, icostheta], [icostheta, sintheta]] , then which of the following is not true? (a) A(theta)^(-1)=A(pi-theta) (b) A(theta)+A(pi+theta) is a null matrix (c) A(theta)^(-1) is invertible for all theta in R (d) A(theta)^(-1)=A(-theta)

The real vaule of theta for which the expression (1+icostheta)/(1-2icos theta) is a purely imaginary number is

If A=[[1, 0],[ 0, 1]] , B=[[1,0],[0,-1]] and C=[[0, 1],[ 1, 0]] , then show that A^2=B^2=C^2=I_2 .

If A=[[1, 0],[ 0,-1]] and B=[[0 ,1], [1, 0]] , then find AB,BA. Show that 'A B!=B A .

If A=[[0,i],[i,1]] and B=[[0, 1],[1, 0]] , find the value of |A|+|B| .

if A=[{:(1,0),(0,1):}]and B=[{:(a,c),(b,d):}], then show that (AB)'=B'A'

If A=[[1, 2, x], [0 ,1 ,0],[ 0, 0, 1]] and B=[[1,-2,y],[0, 1, 0 ],[0, 0, 1]] and A B=I_3 , then x+y equals (a) 0 (b) -1 (c) 2 (d) none of these