If `A=[0 2 3-4]` and `k A=[0 3a2b 24]` , then the values of `k ,\ a ,\ b` , are respectively (a) -6, -12, -18 (b) -6, 4, 9 (c) -6, -4, -9 (d) -6, 12, 18

If A=[(0, 2),( 3,-4)] and k A=[(0, 3a),(2b, 24)] , then the values of k ,\ a ,\ b , are respectively (a) -6, -12, -18 (b) -6, 4, 9 (c) -6, -4, -9 (d) -6, 12, 18

If A={:[(0,2),(3,-4)]:}and kA={:[(0,3a),(2b,24)]:} , then the values of k,a,b are respectively.

If A=[{:(0,2),(3,-4):}] and k A =[{:(0,3a),(2b,24):}], then find the value of b-a-k.

If the arithmetic mean of x ,\ x+3,\ x+6,\ x+9, and x+12 is 10, the x= (a) 1 (b) 2 (c) 6 (d) 4

If 5:4 :: 30 : x , then the value of x is (a) 24 (b) 12 (c) 3/2 (d) 6

Arrange in ascending order : -18, 21, -4, -9, -12, -6, -15, -5, 0, 6, -21

Three numbers are in the ratio 1:2:3 and their HCF is 6, the numbers are (a) 4, 8, 12 (b) 5, 10, 15 (c) 6, 12, 18 (d) 10, 20, 30

The least and greatest values of f(x)=x^3-6x^2+9x in [0,\ 6] , are 3,\ 4 (b) 0,\ 6 (c) 0,\ 3 (d) 3,\ 6

Factorise completely : 4a^(2) - 12 ab + 9b^(2) + 4a - 6b

If x/6+x/4=x/2+3/4, then x= (a) 9 (b) 6 (c) -9 (d) 4