If A and B are two square matrices of the same order then `(A-B)^2` is (A) `A^2-AB-BA+B^2` (B) `A^2-2AB+B^2` (C) `A^2-2BA+B^2` (D) `A^2-B^2`

If A and B are square matrices of the same order then (A+B)^2=A^2+2AB+B^2 implies

if A and B are symmetric matrices of same order then (AB-BA) is :

If A and B are symmetric matrices of same order, then AB-BA is a

If A and B are symmetric matrices of same order, then AB-BA is

If A and B are square matrices of the same order, then (A+B)(A-B) is equal to A^2-B^2 (b) A^2-B A-A B-B^2 (c) A^2-B^2+B A-A B (d) A^2-B A+B^2+A B

If A, B are symmetric matrices of same order, then (AB-BA) is a

If A and B are symmetric matrices of same order, then AB - BA is a

If A and B are square matrices of the same order such that AB=BA, then (A) (A-B)(A+B)=A^2-B^2 (B) (A+B)^2=A^2+2AB+B^2 (C) (A+B)^3=A^3A^2B+3AB^2+B^3 (D) (AB)^2=A^2B^2

If A and B arę square matrices of same order such that AB = A and BA = B, then

If A and B are two square matrices such that B=-A^(-1)BA , then (A+B)^(2) is equal to