Home
Class 12
MATHS
For the system of equations x+y+z=4, y+2...

For the system of equations `x+y+z=4, y+2z=5 and x+y+pz=q` to have no solution (A) `p=1 and q=4` (B) `p=1 and q!=4` (C) `p!=1 and q=4` (D) `p!=1 and q!=4`

Text Solution

AI Generated Solution

Promotional Banner

Similar Questions

Explore conceptually related problems

For what values of p and q the system of equations 2x+py+6z=8, x+2y+qz=5, x+y+3z=4 has no solution. (a). p=2, q ne 3 . (b). p ne 2, q ne 3 (c). p ne 2, q = 3 (d). p =2, q=3

For what values of p and q the system of equations 2x+py+6z=8, x+2y+qz=5, x+y+3z=4 has a unique solution. (a). p = 2, q ne3 (b). p ne 2, q ne 3 (c). p ne 2, q = 3 (d). p =2, q=3

The sum of values of p for which the equations x+y+z=1, x+2y +4z=p and x+4y +10z = p^(2) have a solution is "____"

If p q r!=0 and the system of equation (p+a)x+b y+c z=0 , a x+(q+b)y+c z=0 , a x+b y+(r+c)z=0 has nontrivial solution, then value of a/p+b/q+c/r is a. -1 b. 0 c. 1 d. 2

If p and q are the roots of the equation x^2-p x+q=0 , then (a) p=1,\ q=-2 (b) p=1,\ q=0 (c) p=-2,\ q=0 (d) p=-2,\ q=1

The point of injtersection of the line x/p+y/q=1 and x/q+y/p=1 lies on the line

The value of p and q(p!=0,q!=0) for which p ,q are the roots of the equation x^2+p x+q=0 are (a) p=1,q=-2 (b) p=-1,q=-2 (c) p=-1,q=2 (d) p=1,q=2

if x = a cos^3 theta sin^2 theta and y = a cos^2 theta sin^3 theta and (x^2 + y^2)^p/(xy)^q is independent of theta , then (A) 4p=5q (B) 5p=4q (C) p+q=9 (D) pq=20

if x = a cos^3 theta sin^2 theta and y = a cos^2 theta sin^3 theta and (x^2 + y^2)^p/(xy)^q is independent of theta , then (A) 4p=5q (B) 5p=4q (C) p+q=9 (D) pq=20

If the solution of the equation |(x^4-9)-(x^2+3)|=|x^4-9|-|x^2+3| is (-oo, p]uu[q ,oo) then value of p+q is (a) p=-3 (b) p=-2 (a) q=2 (d) q=3