If a,b,c are in G.P. then the value of `|(a,b,a+b),(b,c,b+c),(a+b,b+c,0)|=` (A) 1 (B) -1 (C) `a+b+c` (D) 0

The value of |{:(1+a,b,c),(a,1+b,c),(a,b,1+c):}| is

If a,b,c are in G.P then (b-a)/(b-c)+(b+a)/(b+c)=

If a ,b ,c ,d are in G.P. prove that: (a b-c d)/(b^2-c^2)=(a+c)/b

If a,b, and c are in G.P then a+b,2b and b+ c are in

If a ,b ,c are in G.P. then prove that (a^2+a b+b^2)/(b c+c a+a b)=(b+a)/(c+b)

If a b c=0 , then find the value of {(x^a)^b}^c (a)1 (b) a (c)b (d) c

If (a-b),\ (b-c),(c-a) are in G.P. then prove that (a+b+c)^2=3(a b+b c+c a)

If a, b, c , d are in G.P. , then shown that (i) (a + b)^(2) , (b +c)^(2), (c + d)^(2) are in G.P. (ii) (1)/(a^(2) + b^(2)), (1)/(b^(2) +c^(2)), (1)/(c^(2) + d^(2)) are in G.P.

If a ,b,c , d are in G.P. prove that (b + c)(b + d) = (c + a)(c+d)

If a,b,c,d………are in G.P., then show that (a+b)^2, (b+c)^2, (c+d)^2 are in G.P.