If `omega` is a cube root of unity , then `|(x+1 , omega , omega^2),(omega , x+omega^2, 1),(omega^2 , 1, x+omega)|` =

If omega is a cube root of unity, then 1+omega = …..

If omega is a cube root of unity, then omega^(3) = ……

If omega is a cube root of unity, then 1+ omega^(2)= …..

If omega is a cube root of unity, then omega + omega^(2)= …..

If omega is a cube root of unity, then |(1-i,omega^2, -omega),(omega^2+i, omega, -i),(1-2i-omega^2, omega^2-omega,i-omega)| =

If omega is a cube root of unity, then Root of polynomial is |(x + 1,omega,omega^(2)),(omega,x + omega^(2),1),(omega^(2),1,x + omega)|

If omega is a complex cube root of unity, then a root of the equation |(x +1,omega,omega^(2)),(omega,x + omega^(2),1),(omega^(2),1,x + omega)| = 0 , is

If omega is cube roots of unity, prove that {[(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)]+[(omega,omega^2,1),(omega^2,1,omega),(omega,omega^2,1)]} [(1),(omega),(omega^2)]=[(0),(0),(0)]

If omega is cube roots of unity, prove that {[(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)]+[(omega,omega^2,1),(omega^2,1,omega),(omega,omega^2,1)]} [(1),(omega),(omega^2)]=[(0),(0),(0)]

If 1.omega, omega^2 are the roots of unity, then Delta=|(1,omega^n,omega^(2n)),(omega^n,omega^(2n),1),(omega^(2n),1,omega^n)| is equal to