m women and n men are too be seated in a row so that no two men sit together. If `mgtn` then show that the number of wys in which they can be seated is `(m!(m+1)!)/((m-n+1)!)`

m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

If n men and m women are to be seated in a row so that no two women sit together . If ngtm , then show that number of ways in which they can be seated is (n!(n+1)!)/((n-m+1)!)

In how may ways can 6 girls and 4 boys be seated in a row so that no two boys are together ?

In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together?

In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together?

In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together?

In how many ways can 5 girls and 3 boys be seated in a row so that no two boys are together?

Number iof ways in which m men and n women can be arranged in a rwo so that no two women are together is m!^(m=1)P_n Also number oif ways in which m men and n women can be seated in a row so that all the n women are together is (m=1)!n! On the basis of above informatiion answer the following question the no of ways in which 10 boys & 5 girls: seated in row so that no boy sits between girls

Number iof ways in which m men and n women can be arranged in a rwo so that no two women are together is m!^(m=1)P_n Also number oif ways in which m men and n women can be seated in a row so that all the n women are together is (m=1)!n! On the basis of above informatiion answer the following question: Therre are 10 intermediate stations between two places P and Q. the number of ways in 10 boys &5 girls can be seated in a row so that no boy sits between girls

Number iof ways in which m men and n women can be arranged in a rwo so that no two women are together is m!^(m=1)P_n Also number oif ways in which m men and n women can be seated in a row so that all the n women are together is (m=1)!n! On the basis of above informatiion answer the following question: Number of ways in which 10 boys and 5 girls can be seated in a row so that no boy sits between girls is (A) 5!xx10_P_5 (B) 5!xx11_P_5 (C) 10!xx11_P_5 (D) 5!xx11