A five-digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition. The total number of ways this can done is

A five digit number divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 and 5, without repetition. The total number of ways this can be done, is

A five digit number divisible by 3 is to be formed using the digits 0,1,3,5,7,9 without repetitions. The total number of ways this can be done is

A five digit number divisible by 3 is to be formed using the digits 0,1,2,3,4 and 5 without repetitioon. If the tota number of ways in which this casn bedone is n^3, then |__n= (A) 720 (B) 120 (C) 48 (D) 12

Statement-1: A 5-digit number divisible by 3 is to be formed using the digits 0,1,2,3,4,5 without repetition, then the total number of ways this can be done is 216. Statement-2: A number is divisible by 3, if sum of its digits is divisible by 3.

A three-digit number is to be formed using the digits 0, 1, 2, 3, 4, and 5, without repetition.

A 5-digit number divisible by 3 is to be formed using the number 0,1,2,3,4 and 5 without repetiition. Find total of ways in whiich this can be done.

A five digits number divisible by 3 is to be formed using the number 0,1,2,3,4 and 5 without repetition. The number of such numbers are m^(3) then m is equal to

An eight digit number divisible by 9 is to be formed using digits from 0 to 9 without repeating the digits. The number of ways in which this can be done is

Five digit number divisible by 3 is formed using 0 1 2 3 4 6 and 7 without repetition Total number of such numbers are

The number of five digit numbers formed with the digits 0, 1, 2, 3, 4 and 5 (without repetition) and divisible by 6 are