Let `A={x_1,x_2,x_3,x_4,x_5},B={y_1,y_2,y_3,y_4}`, Function f is defined from A to B. Such that `f(x_1)=y_1`, and `f(x_2)=y_2` then, number of onto functions from A to B is (A) 12 (B) 6 (C) 18 (D) 27

Consider set A = {x_(1), x_(2), x_(3), x_(4), x_(5)} and set B = {y_(1), y_(2), y_(3)} . Function f is defined from A to B. Number of function from A to B such that f(x_(1)) = y_(1) and f(x_(2)) != y_(2) is

Consider set A = {x_(1), x_(2), x_(3), x_(4), x_(5)} and set B = {y_(1), y_(2), y_(3)} . Function f is defined from A to B. Number of function from A to B such that f(x_(1)) = y_(1) and f(x_(2)) != y_(2) is

If A={1,2,3},\ B={x , y} , then the number of functions that can be defined from A into B is 12 b. 8 c. 6 d. 3

Consider three sets A = {1, 2, 3}, B = {3, 4, 5, 6}, C = {6, 7, 8, 9}. R_(1) is defined from A to B such that R_(1) = {(x, y) : 4x lt y, x in A, y in B} . Similarly R_(2) is defined from B to C such that R_(2) = {(x, y) : 2x le y, x in B and y in C } then R_(1)oR_(2)^(-1) is

Let f(x) be real valued continous funcion on R defined as f(x) = x^(2)e^(-|x|) Number of points of inflection for y = f(x) is (a) 1 (b) 2 (c) 3 (d) 4

If A={1,2,3,4} . Prove that f defined by f={(x,y) , x+y=5} is function from A to A

If function y=f(x) has only two points of discontinuity say x_1,x_2, where x_1,x_2<0, then the number of points of discontinuity of y=f(-|x+1|) is (a) 0 (b) 2 (c) 6 (d) 4

Let A = {x_(1),x_(2),x_(3),x_(4), x_(5), x_(6),x_(7), x_(8)}, B= { y_(1), y_(2), y_(3), y_(4) } . The total number of function f : A to B that are onto and there are exactly three elements x in A such that f(x) = y_(1) is :

Let A = {x_1, x_2, x_3, ,x_7},B={y_1, y_2, y_3} The total number of functions f: A->B that are onto and there are exactly three element x in A such that f(x)=y_2 is equal to a. 490 b. 510 c. 630 d. none of these

Let A={x_(1),x_(2),x_(3)....,x_(7)},B={y_(1)y_(2)y_(3)} . The total number of functions f:AtoB that are onto and ther are exactly three elements x in A such that f(x)=y_(2) , is equal to