If the number of terms in `(x +1+ 1/x)^n` n being a natural number is 301 the n=

If the number of terms in (x + 1 + (1)/(x))^(n) (n in I ^(+) " is " 401 , then n is greater then

If n is a natural number, then sqrt(n) is:

The number of terms in the expansion of (x^2+1+1/x^2)^n, n in N , is:

The number of natural numbers n for which (15n^2+8n+6)/n is a natural number is:

If the sum of first n even natural numbers is equal to k times the sum of first n odd natural number then k= a. 1/n b. (n-1)/n c. (n+1)/(2n) d. (n+1)/n

If the sum of first n even natural numbers is equal to k times the sum of first n odd natural number then k= 1/n b. (n-1)/n c. (n+1)/(2n) d. (n+1)/n

let S_(n) denote the sum of the cubes of the first n natural numbers and s_(n) denote the sum of the first n natural numbers , then sum_(r=1)^(n)(S_(r))/(s_(r)) equals to

In the expansion of (x^2+1+1/(x^2))^n ,n in N , number of terms is 2n+1

In the expansion of (x^2+1+1/(x^2))^n ,n in N , number of terms is 2n+1

For some natural number 'n', the sum of the first 'n' natural numbers is 240 less than the sum of the first (n+5) natural numbers. Then n itself is the sum of how many natural numbers starting with 1.