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If ^n C0/2- ^n C1/3+^n C2/4-…….+(-1)^n...

If `^n C_0/2- ^n C_1/3+^n C_2/4-…….+(-1)^n ^n C_n/(n+2)`= `1/(1999x2000) then n`= (A) 1998 (B) 1999 (C) 2000 (D) 2001

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