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Prove that the numbers 49, 4489, 444889,...

Prove that the numbers 49, 4489, 444889, …. Obtained by inserting 48 into the middle of the preceding numbers are square of integers.

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Prove that in a sequence of numbers 49,4489,444889,44448889 in which every number is made by inserting 48-48 in the middle of previous as indicated, each number is the square of an integer.

Prove that in a sequence of numbers 49,4489,444889,44448889 in which every number is made by inserting 48-48 in the middle of previous as indicated, each number is the square of an integer.

If a_na_(n-1)a-(n-2),.,a_3,a_2,a-1 be a digit having a_1,a_2,a_3,…..a_n t unti, thens hundred places respectively. Then a_n a_(n-1) a_(n-2)….a_3a_2a_1= a_nxx1+a_2xx10^2+a_3xx10^3+…..+a_n10^(n-1) On the basis of above information answer the following question For a sequence {t_n},t_1=49, t_2= 4489, t_3=444889 in which every number is made by inserting 48 in the middle of the previous number. The for all nepsilonN, t_n is (A) square of an odd integer (B) divisible by 3 (C) divisible by 9 (D) none of these

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